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Posts
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Everything posted by Chen
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Ok,I wonder if our software can be considered this.
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Dear sir: For the bi-facial module system , when calculating the cable loss of strings, should the current on the rear side of the modules be considered in our software? thanks!
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ok,I agree with your viewpoint, but do you think this calculation is reasonable? if the fornt side of module receive irradiance of 1000 W/m², and the rear side of module receive irradiance of 200 W/m², front side:(f × 22- f × 22) / (f × 22) = 0% (relative) rear side:(f × 21.34 - f × 22) / (f × 22) = -3% (relative)
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thanks
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Dear pvsyst team: If I have an irregular trackers system, with some different pitches and GCR, what is the difference between the reference trackers and automatic mode ( deselecting the reference pair of trackers)?what is the automatic mode? thanks!
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Will the temperature increase and power decrease when local solar cells of photovoltaic modules experience hot spots be considered in the power generation simulation?thanks
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Dear PVsyst team: I saw an article in the literature that mentioned a comparison between the settings of UC and UV and actual simulation tests. Can we see if there is still a need to optimize UC for bifacial modules? thanks de Oliveira A K V, Braga M, Naspolini H F, et al. Validation of Thermal Models for Bifacial Photovoltaic Systems under Various Albedo Conditions[J]. ESS Open Archive eprints, 2024, 63: 06323163. https://onlinelibrary.wiley.com/doi/abs/10.1002/pip.3892 CTG_PIP_Temperature.pdf
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OK IRev = Iph +aRev *V,for aRev=800mA/V^2, 800/1000*(-5.2)*(-5.2)= 21.632 (A) ;the externally forced current is 7.93A; how to calculate IRev? thanks
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Excuse me, Prof.Andre Mermoud is I the reverse current in this formula,so a more accurate representation would be IRev = Iph +aRev *(V+Rs * IRev) ;and the externally forced current is IRev? thanks for reply.
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as we can see the three values on the figure, the V (-5.2V),I(7.93A) and P(128W),Is there a formula that can explain their relationship,thanks!
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Dear pvsyst team: I am using this software to simulate the temperature and power when a cell is local shading. I find that “externally forced current= 4.4A” is all the same for the different solar modules. What does it mean? thanks!
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sorry ,i find a mistake in my sentence,the solar size is 210mm*105mm,so final result is 44/ ( 0.21*0.105*29) =25 = 94 (℃).The results are basically the same as those of pvsyst.
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just choose "Generic_Mono_700W_Half_Bifacial.PAN" for example. Here, Uc = 29 W/m²·k, or say Uc = 29 W/m²·℃, and the size of the cell is 150 mm*210 mm. For one solar cell shading, if the temperature rises by 1 ℃, it need power 0.21*0.15*29= 0.9135(W),and the cell power consumption now is 45W,45/0.9135= 48.17 (℃),by adding 25 ° ambient,the result is 73.16(℃),which is not quite consistent with the results shown on the graph (95℃).Can you help me check if there are any errors in my deduction? thanks
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in my opinion,the module VOC corrected by irradiance value and ambient temperature will be more reasonable for system design.