ShivamPandey Posted August 15 Share Posted August 15 What should be the correct approach for the partition of half-cut cell modules in fixed-tilt tables. For 2P*13 table size, strung in U 4*number of modules per string i.e. 4 in the Y axis and 13 in X axis For 2P*26 table size, strung in U 4*1 i.e. 4 in the Y axis and 1 in X axis Link to comment Share on other sites More sharing options...
Michele Oliosi Posted August 15 Share Posted August 15 Half-cut cell modules in portrait, strung in U (2TU) have: - Partitions in y = 2, partitions in x = 1 For wider tables which are 2 strings across (26 = 2*13) still strung in U: - Partitions in y = 2, partitions in x = 2 https://www.pvsyst.com/help/shadings_partitioninstrings.htm Link to comment Share on other sites More sharing options...
dtarin Posted August 15 Share Posted August 15 3 hours ago, ShivamPandey said: For 2P*26 table size, strung in U 4*1 i.e. 4 in the Y axis and 1 in X axis It may depend on where these tables are in the array and the site conditions. For an exterior table that has significant tree shading (or other object shading), strung in U may be better (2x2). For interior tables, where most of the shading will be from the rows in front, stringing across the entire table (and not in U) is likely better (4x1). Link to comment Share on other sites More sharing options...
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